EXAMPLE 1
Evaluate inverse trigonometric functions
Evaluate the expression in both radians and degrees.
a.
cos
–1
3
2
√
SOLUTION
a.
When
0
θ
π
or
0°
180°,
the angle
whose cosine is
≤
≤
≤
θ
≤
3
2
√
cos
–1
3
2
√
θ
=
π
6
=
cos
–1
3
2
√
θ
=
=
30°