EXAMPLE 1
Evaluate inverse trigonometric functions
Evaluate the expression in both radians and degrees.
a.
cos–1
3
2
√
SOLUTION
a.
When 0    θ     π or 0°           180°, the angle whose cosine is
≤
≤
≤
θ
≤
3
2
√
cos–1
3
2
√
θ
=
π
6
=
cos–1
3
2
√
θ
=
=
30°